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Static and kinetic friction

Friction has two regimes, and the static one has a maximum rather than a fixed value.

Static vs kinetic

Static friction acts when surfaces do not slide; it adjusts itself to exactly cancel the applied push, up to a maximum of mu_s N. Once sliding starts, kinetic friction takes over with a fixed magnitude mu_k N opposing the sliding direction. Because mu_s exceeds mu_k, it takes more force to start a slide than to keep one going, which is why heavy boxes lurch.

f_s \le \mu_s N, \quad f_k = \mu_k N

The coefficient and N

The coefficient of friction is dimensionless and depends only on the pair of surfaces, not on the size of the forces. The friction formula uses the normal force, not the weight, so on an incline friction is mu times mg cos(theta), weaker than on level ground. On a level surface at rest, N equals mg.

f_k = \mu_k mg\cos\theta

Worked example

A 5.0 kg block slides down a 37 degree incline with mu_k = 0.25, using sin(37) = 0.60 and cos(37) = 0.80. Gravity pulls along the slope with 49(0.60) = 29.4 N. The normal force is 49(0.80) = 39.2 N, so kinetic friction is 0.25 times 39.2 = 9.8 N up the slope. The net 19.6 N along the slope gives a = 19.6/5.0 = 3.92 m/s^2 down the incline.

a = \frac{mg\sin\theta - \mu_k mg\cos\theta}{m} = \frac{29.4 - 9.8}{5.0} = 3.92 \text{ m/s}^2

Flashcard

f_s \le \mu_s N

Static friction can be anything up to a maximum

Static friction is reactive, matching the applied force push for push until its ceiling. Only at the moment sliding impends does it reach its maximum value mu_s times N.

Check your understanding

A 20 kg crate sits on a level floor with mu_s = 0.40 and mu_k = 0.30. What horizontal force keeps it sliding at constant speed?

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