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Integrals Over Flat Regions

A double integral adds up the values of a function across a two-dimensional region, one thin rectangle at a time.

Slicing two ways

Just as a single integral sums thin rectangles under a curve, a double integral sums thin boxes under a surface over a region R. Each box has base area dA and height f, so the integral measures signed volume when f is a height. If f is instead a density, the same integral gives total mass over the region.

\iint_R f(x,y)\,dA

Iterated integrals

In practice you compute a double integral as an iterated integral, doing the inner integral first while treating the outer variable as constant. For the rectangle example integrating xy over 0 to 2 in y and 0 to 3 in x, the inner integral gives 2x, and integrating that from 0 to 3 gives 9. Two nested single integrals replace one intimidating double symbol.

\int_0^3 \int_0^2 xy\,dy\,dx = 9

Swapping the order

The area element dA can be read as dx dy or dy dx, and the two orders give the same answer when the region allows it. Switching order is a favorite trick because one order may have an antiderivative the other lacks. For non-rectangular regions, describe the boundary as functions and let the inner limits depend on the outer variable.

dA = dx\,dy = dy\,dx

Flashcard

\iint_R f(x,y)\,dA

Signed volume under the surface over region R

The double integral sums the height f over every small patch of the region. Negative values count as volume below the xy-plane, which is why the result is called signed volume.

Check your understanding

Evaluate the iterated integral of x, integrated over y from 0 to 3 and then over x from 0 to 2.

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