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Antiderivatives Unlock the Integral

The Fundamental Theorem says the two great ideas of calculus, slopes and areas, are inverse operations.

Defining the Integral

The definite integral of f from a to b is the limit of Riemann sums as the slices get infinitely thin. It measures signed area: regions above the axis count positive, regions below count negative. A function can be negative everywhere and still have a perfectly good, negative integral.

\int_a^b f(x)\,dx = \lim_{n\to\infty}\sum_{i=1}^{n} f(x_i^*)\,\Delta x

FTC Part 1

Define an area-so-far function by integrating f from a fixed point a up to a variable endpoint x. Differentiate that accumulation and you get back f itself. This is the theorem's first half: integration, run forward, is undone by differentiation.

\frac{d}{dx}\int_a^x f(t)\,dt = f(x)

FTC Part 2

The second half says you can evaluate a definite integral with any antiderivative F: the answer is F(b) minus F(a), no limits required. For f(x) = x^2 on [0, 2], an antiderivative is x^3/3, so the integral is 8/3 minus 0. What took an infinite sum by hand is now two evaluations.

\int_a^b f(x)\,dx = F(b) - F(a)

Flashcard

\int_a^b f(x)\,dx = F(b)-F(a)

Evaluation form of the Fundamental Theorem

If F is any antiderivative of f, the definite integral equals the antiderivative evaluated at the endpoints and subtracted. This bypasses computing Riemann sums entirely.

Check your understanding

A car's velocity is v(t) = 2t for 0 to 3 seconds. What does the integral of v from 0 to 3 give, and what is its value?

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